December 24, 2025

date in Gregorian calendar
rdfs:label
"December 24, 2025"@en
skos:altLabel
"24 December 2025"@en
schema:description
"date in Gregorian calendar"@en
schema:dateModified "2026-07-22T17:47:50+00:00"^^xsd:dateTime
schema:version 2521252452
wikibase:identifiers 0
wikibase:sitelinks 4
wikibase:statements 8
p:P2894 wd:statement/Q69307764-215B10C7-F351-4D5C-B602-5A7C9C342851
p:P31 wd:statement/Q69307764-0D463922-EF7D-4EB3-A505-0891DBA6CD53
wd:statement/Q69307764-54E603E1-3617-4083-B62B-C6404F4C8213
wd:statement/Q69307764-94f2319c-4751-53bd-f029-b683ff2e2a49
p:P361 wd:statement/Q69307764-F6020A09-7B5A-4A8A-90C1-2A2F0D735B8D
p:P373 wd:statement/Q69307764-50aad5d6-4eaa-c52f-af29-54ca84de9208
p:P585 wd:statement/Q69307764-FFBAC96E-5C3F-435B-806A-F73CFA5F8504
p:P910 wd:statement/Q69307764-e49c4615-416b-5b2c-426b-c34923c63ded
wdt:P2894 Wednesday
wdt:P31 December 24
calendar day of a given year
fourth Wednesday in December
wdt:P361 December 2025
wdt:P373 "2025-12-24"
wdt:P585 "2025-12-24T00:00:00+00:00"^^xsd:dateTime
wdt:P910 Category:2025-12-24
Download as:
TurtleJSON-LDRDF/XML
data from SPARQL profile: Wikidata