December 25, 2025

date in Gregorian calendar
rdfs:label
"December 25, 2025"@en
skos:altLabel
"25 December 2025"@en
schema:description
"date in Gregorian calendar"@en
schema:dateModified "2026-07-22T17:48:04+00:00"^^xsd:dateTime
schema:version 2521252560
wikibase:identifiers 0
wikibase:sitelinks 5
wikibase:statements 8
p:P2894 wd:statement/Q69307765-8F1AD64D-D438-4E1C-86BF-9A76685A2589
p:P31 wd:statement/Q69307765-19C942CD-E1AD-4B66-AA69-C55E7903BA4A
wd:statement/Q69307765-53A70E31-6274-4032-AA3C-F350352834C0
wd:statement/Q69307765-902dc9e3-41ae-f023-8190-be38cd7e59e8
p:P361 wd:statement/Q69307765-730B3E8F-DF03-4B5A-ACB6-DF04BFE5EC63
p:P373 wd:statement/Q69307765-0801a74e-4388-717a-957b-805d1a7c9c84
p:P585 wd:statement/Q69307765-8CF60FE2-BB42-4E5B-80A6-8F8730E6FF26
p:P910 wd:statement/Q69307765-4b4af5e0-4579-2d17-69a2-7f37ede4f3ae
wdt:P2894 Thursday
wdt:P31 December 25
calendar day of a given year
fourth Thursday in December
wdt:P361 December 2025
wdt:P373 "2025-12-25"
wdt:P585 "2025-12-25T00:00:00+00:00"^^xsd:dateTime
wdt:P910 Category:2025-12-25
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data from SPARQL profile: Wikidata